(y^2-4)(3y-9)=0

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Solution for (y^2-4)(3y-9)=0 equation: 


Simplifying
(y2 + -4)(3y + -9) = 0

Reorder the terms:
(-4 + y2)(3y + -9) = 0

Reorder the terms:
(-4 + y2)(-9 + 3y) = 0

Multiply (-4 + y2) * (-9 + 3y)
(-4(-9 + 3y) + y2(-9 + 3y)) = 0
((-9 * -4 + 3y * -4) + y2(-9 + 3y)) = 0
((36 + -12y) + y2(-9 + 3y)) = 0
(36 + -12y + (-9 * y2 + 3y * y2)) = 0
(36 + -12y + (-9y2 + 3y3)) = 0
(36 + -12y + -9y2 + 3y3) = 0

Solving
36 + -12y + -9y2 + 3y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '3'.
3(12 + -4y + -3y2 + y3) = 0

Ignore the factor 3.

Subproblem 1
Set the factor '(12 + -4y + -3y2 + y3)' equal to zero and attempt to solve:

Simplifying
12 + -4y + -3y2 + y3 = 0

Solving
12 + -4y + -3y2 + y3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.

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